Hi,
I recently did a synthesis and my product was pure except for a single impurity absorbing only in very high wavelength. I believe the impurity to be Diethly amine. Does anybody knows the UV cutoff for DEA or does any body have a link to an UV cutoff table??
Greatly appreciated
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By John B on Friday, June 7, 2002 - 04:35 am:
CRC handbook has a section for common liquids but DEA was not listed.
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By Anonymous on Friday, June 7, 2002 - 05:50 am:
Jean-Philippe,
According to Snyder et. al. (Practical HPLC Method Development) the cutoff for TEA (yes I know it's not DEA but should have the same cutoff) they used a 10 mM TEA*HCl TEA mix down to 200 nm. Your impuritty is probably not DEA if it is absorbing at anything over about 220 nm.
Regards,
Mark
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By Cindy on Friday, June 7, 2002 - 07:01 am:
Jean,
Check out here:
http://home.planet.nl/~skok/techniques/hplc/eluotropic_series_extended.html
Cindy
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By Jean-Philippe Lambert on Friday, June 7, 2002 - 09:40 am:
Thanks for all your quick answers, very appreciated.
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By Chris Pohl on Monday, June 10, 2002 - 08:45 am:
DEA doesn't absorb in the ultraviolet but hydroxide anion does. Perhaps this is the source of your absorbance.
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By Benjamin on Monday, June 10, 2002 - 01:41 pm:
Jean;
I have no experience with DEA, but I can tell you the following about TEA. It does absorb strongly below 240nm in Water and in Hexane solutions. The cutoff of a 0.1M solution in H20 is 230NM.
I believe some of the comments above refer to HCl salts rather than the free bases.
Benjamin esquivel
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By Chris Pohl on Monday, June 10, 2002 - 02:28 pm:
TEA doesn't absorb in the UV either. The cutoff mentioned above is likely due to the presence of oxidized impurities (manifested by a yellow-orange color), chloride ion (although this couldn't be responsible for a cutoff as high as 230 nm) or hydroxide anion (relevant only in the freebase form).
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