Hi felows,
IŽd like to know how to convert the polarity of Methanol 90% : water 10% for acetonitrile and water, for exemple.
How much is it gonna be?
Is there some table?
Thaks,
![]()
![]()
![]()
![]()
By Bernd Mischke on Friday, March 19, 2004 - 03:58 am:
Hi Paulo,
try it with 70% ACN. But don't forget, that this solvent has other types of properties so like less proton donor and more proton acceptor function. Depending on Your samples You can get selectivity changes.
![]()
![]()
![]()
![]()
By HW Mueller on Friday, March 19, 2004 - 07:14 am:
You want to have the same elution power as with 90+10 MeOH+H2O? A nomograph in Snyder, Glajch, Kirkland, Practical HPLC Development, Wiley, 1988, p. 32 gives ~ 86+14 for ACN+H2O.
![]()
![]()
![]()
![]()
By Paulo Camuri on Monday, March 22, 2004 - 10:49 am:
Hi Mueller,
is this a monography (in a journal) or a book?
Anyway, I apreciate your help.
Paulo Camuri
![]()
![]()
![]()
![]()
By Tom Mizukami on Monday, March 22, 2004 - 12:00 pm:
See figure 3.
http://www.mac-mod.com/pdf/PolarEmbed3.pdf
![]()
![]()
![]()
![]()
By Uwe Neue on Monday, March 22, 2004 - 03:26 pm:
Schoenmakers rule:
f (MeCN) = 0.32 f (MeOH) ^2 + 0.57 F (MeOH)
Haddad rule:
f(MeCN) = 0.9 * f(MeOH)^2 -0.21 f(MeOH) +0.126
f is the volume fraction.
The truth is most of the time in between