By andr on Wednesday, January 26, 2000 - 03:36 am:
Has someone an experience how to define LOD or LOQ from calibration curve according to ICH:
- lod = 3,3*sd/s
- loq=10*sd/s
s=slope
sd = stand. deviation of response - or residual st.dev.of reg. line or stdev of y-intercept of reg. line
I tried to get some figures but without sucess.
By Anonymous on Thursday, March 9, 2000 - 01:57 pm:
the way I have done it, is the stddev of the y-intercept = SD. Your formulas are correct and your answer will be in whatever units the curve is in.
By Anonymous on Monday, March 13, 2000 - 09:58 am:
See LC/GC volume 16, number 10, October 1998, pg. 922-924 for a discussion on how to calculate LOD/LOQ using the formulas you're asking about.
By Anonymous on Friday, March 17, 2000 - 01:27 pm:
In the article cited (LC-GC Oct 10, 1998), the formulas are listed. I have had trouble applying
them because one of the factors it requires is the sum of x residuals.
I must have a really old version of Excel because there is no mention of x residuals in my package.
Any words of wisdom?
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